I was very impressed by the responses I got to my earlier request for help.
I've found two ways
to solve my problem. The first involved using an unchecked conversion to
convert the float type into a modular type and then see if the difference
was less than a certain amount. I found a differnce of less than four to
suffice for my purposes. The code to implement this is shown at the bottom.
Robert Eachus' solution of using a Fixed Point representation is the one I
like best. See his earlier post for how to implement this. As the saying
goes, "You learn something everyday."
When (if) I get a paper published on an alternative algorithm to the
Traveling Salesman Problem, I'll be sure to drop a line here giving a
pointer to it. (As a teaser, I think I've found a way to find the solution
in N**2 rather than N! time, at least for points lying on the 2D Cartesian
plane.) My plan now is to hit up the ACM's Trans. on Mathematical Software
with a paper within the next two to three months. It will be nice to see a
reference in there to an algorithm implemented in something other than Fortran!
Thanks again for all the help!
Here's my code to compare two My_Float variables. Obviously this could
easily be turned into a generic function, but I'm going rewrite my code
using Fixed Point instead.
function "="(Left, Right: in My_Float) return Boolean is
type MFR is mod 2**My_Float'Size;
for MFR'Size use My_Float'Size;
package MFR_IO is new Ada.Text_IO.Modular_IO(MFR);
is new Ada.Unchecked_Conversion(My_Float, MFR);
is new Ada.Unchecked_Conversion(MFR, My_Float);
Left_MFR: MFR := To_MFR(Left);
Right_MFR: MFR := To_MFR(Right);
Diff: constant MFR := 4;
if Left_MFR = Right_MFR then
elsif Left_MFR < Right_MFR then
if Right_MFR-Left_MFR < Diff then
if Left_MFR-Right_MFR < Diff then
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