Alexandre E. Kopilovitch writes:
> class GentleThread : public Runnable {
> ...
> }
>
> class BruteThread : public Runnable {
> ...
> }
>
> will inherit an identical implementation of the interface Runnable from the
> ancestor class. Do you see the difference?
No. It has been said that Runnable is a pure virtual class. So there is no
inherited identical implementation.
Pascal.
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